Answered

Westonci.ca is the premier destination for reliable answers to your questions, brought to you by a community of experts. Get detailed answers to your questions from a community of experts dedicated to providing accurate information. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

what are the real zeros for the function
f(x)=x^2-3x-28

Sagot :

Factor the equation: (x-7)(x+4) Solve for X: X-7=0 x+4=0 X=7 x=-4 A zero is when the function crosses the x-axis which is solved by setting the function equal to zero.
konrad509
[tex]x^2-3x-28=0\\ x^2-7x+4x-28=0\\ x(x-7)+4(x-7)=0\\ (x+4)(x-7)=0\\ x=-4 \vee x=7[/tex]
Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.