Answered

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A 15kg block has a constant acceleration of 2.2m/s^2 down a 30 degree incline
what is the magnitude of the friction force on the block

Sagot :

please find word document attached.
View image ammar97
icedraptor88
Use Newton's Second law of motion and plug in what you know:
15sin30-friction=15a
15 times 9.8 times 0.5-15 times 2.2 =Friction
So Friction = 73.5 -33, or 40.5 Newtons
Hope this helps!
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