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A number is such that its ten digit is twice its unit digit. Prove that the number itself must be seven times the sum of its digit

Sagot :

x - ten digit
y - unit digit

[tex]x=2y\\ 10x+y=7(x+y)\\\\ 10\cdot2y+y=7(2y+y)\\ 20y+y=14y+7y\\ 21y=21y \Rightarrow y\in \mathb{R}\Rightarrow x\in \mathb{R}[/tex]

So it's true.
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