Answered

Welcome to Westonci.ca, your one-stop destination for finding answers to all your questions. Join our expert community now! Get immediate and reliable solutions to your questions from a community of experienced experts on our Q&A platform. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

A 15kg. Blob of "space clay" moving at a speed of 3m/s slams I to a 12.5 blob of "space clay" at rest. They stick together after colliding, but what is their new speed?

What's the formula used and how do you solve this...?

Sagot :

AL2006
Use the principle of conservation of momentum ... momentum after the collision is equal to the momentum before it.

Momentum = (mass) x (speed).

Momentum before the collision:
Big blob . . . (15) x (3) = 45 kg-m/s
Little blob . . (12.5) x (0) = zero.
Total . . . . . . 45 kg-m/s

Momentum after they meet and stick:
Combined blob . . . (15+12.5) x (speed)

Momentum after = momentum before:

(27.5) x speed = 45 kg-m/s

Divide each side by 27.5 :

Speed = 45 / 27.5  =  1.636 m/s  (rounded)
Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.