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Sagot :
Change in Momentum = mv - mu.
u = 0, v = 10 m/s. Note ball accelerated from rest, so initial velocity = 0. u =0
Change in Momentum = mv - mu = 3*10 - 3*0 =30.
Change in Momentum = 30 kgm/s.
u = 0, v = 10 m/s. Note ball accelerated from rest, so initial velocity = 0. u =0
Change in Momentum = mv - mu = 3*10 - 3*0 =30.
Change in Momentum = 30 kgm/s.
Answer
The change in momentum of ball is 30kg m/sec .
Explanation:
Formula for change in momentum is given by .
[tex]\Delta P = mv -mu[/tex]
Where m is mass , v is final velocity and u is initial velocity .
As given
A 3-kilogram ball is accelerated from rest to a speed of 10 m/sec.
m = 3
u = 0 m/sec
v = 10 m/sec
Putting values in the formula
[tex]\Delta P = 3\times 10 -3\times 0[/tex]
[tex]\Delta P = 30\ kg\ m/sec[/tex]
Therefore the change in momentum of ball is 30kg m/sec .
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