Timon65
Answered

Discover answers to your questions with Westonci.ca, the leading Q&A platform that connects you with knowledgeable experts. Discover reliable solutions to your questions from a wide network of experts on our comprehensive Q&A platform. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.

A 3-kilogram ball is accelerated from rest to a speed of 10 m/sec. What is the ball's change in momentum?

Sagot :

olemakpadu
Change in Momentum =  mv - mu.

u = 0, v = 10 m/s.  Note ball accelerated from rest, so initial velocity = 0. u =0

Change in Momentum =  mv - mu = 3*10 - 3*0 =30.

Change in Momentum = 30 kgm/s.

Answer

The change in momentum of ball is 30kg m/sec .

Explanation:

Formula for change in momentum is given by .

[tex]\Delta P = mv -mu[/tex]

Where m is mass , v is final velocity and u is initial velocity .

As given

A 3-kilogram ball is accelerated from rest to a speed of 10 m/sec.

m = 3

u = 0 m/sec

v = 10 m/sec

Putting values in the formula

[tex]\Delta P = 3\times 10 -3\times 0[/tex]

[tex]\Delta P = 30\ kg\ m/sec[/tex]

Therefore the change in momentum of ball is 30kg m/sec .



We hope our answers were helpful. Return anytime for more information and answers to any other questions you may have. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.