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solve for d:
2d+1/6=6(1/3d+1)

Sagot :

2d+1/6=2d+6 (I distributed the 6 to what was in the parentheses)
2d-2d=6-1/6 (I subtracted 2d from both sides to get the variables on one side and               1/6 from both sides to get the variables by themselves)
0=35/6 (combined like terms)
0=35/6 is an untrue statement so x doesn't exist

eah
2d + 1/6 = 6(1/3d + 1)
2d + 1/6 = 2d + 6
2d - 2d = 6 - 1/6
0d = 35/6

[tex]Ans: \O[/tex]