Westonci.ca is your go-to source for answers, with a community ready to provide accurate and timely information. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.
Sagot :
The formula for the perimeter of a rectangle is 2(l+w)
The formula for the area of a rectangle is lw
First you need to solve for w and l
w+12=l
2(l+w)=44
2[(w+12)+w]=44 (since you know w+12=l, you can plug that into the l value of the second equation. Now you only have 1 variable to solve for, w, instead of 2)
2(2w+12)=44 (I combined like terms inside the parentheses)
4w+24=44 (I distributed 2 to everything inside the parentheses)
4w=20 (I subtracted 24 from both sides)
w=5 (divide both sides by 4)
Now that we know what w is, we can plug that into the first equation to solve for l
5+12=l
l=17
Now we solve for area
17x5=237.16
A=237.16 cm^2
The formula for the area of a rectangle is lw
First you need to solve for w and l
w+12=l
2(l+w)=44
2[(w+12)+w]=44 (since you know w+12=l, you can plug that into the l value of the second equation. Now you only have 1 variable to solve for, w, instead of 2)
2(2w+12)=44 (I combined like terms inside the parentheses)
4w+24=44 (I distributed 2 to everything inside the parentheses)
4w=20 (I subtracted 24 from both sides)
w=5 (divide both sides by 4)
Now that we know what w is, we can plug that into the first equation to solve for l
5+12=l
l=17
Now we solve for area
17x5=237.16
A=237.16 cm^2
Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. We appreciate your time. Please come back anytime for the latest information and answers to your questions. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.