Welcome to Westonci.ca, where your questions are met with accurate answers from a community of experts and enthusiasts. Experience the convenience of getting accurate answers to your questions from a dedicated community of professionals. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.
Sagot :
what is the height of Fort Collins High School?
If found, use the formula, V=x/t-----------------(x=distance; t=time)
You have three known variables:
Acceleration - [tex]9.8m/s^2[/tex]
Time - [tex]1.85s[/tex]
Initial Velocity - [tex]0m/s[/tex]
For the first part of your question:
[tex]v = u + at v = (0)+(9.8)(1.1) v = 10.78 m/s
v=11 m/s (2 significant figures)[/tex]
For the second part of your question:
[tex]v=u+at v=(0)+(9.8)(1.85) v=18.13 m/s [/tex]
This still needs to be converted to m/h:
[tex]18.13m/s = 18.13\times 3600 metres/h=65628 metres/hour 65628 metres/hour = 65628\div1600 mi/h = 40.7925 mi/h = 41 mi/hr (2 significant figures) [/tex]
Acceleration - [tex]9.8m/s^2[/tex]
Time - [tex]1.85s[/tex]
Initial Velocity - [tex]0m/s[/tex]
For the first part of your question:
[tex]v = u + at v = (0)+(9.8)(1.1) v = 10.78 m/s
v=11 m/s (2 significant figures)[/tex]
For the second part of your question:
[tex]v=u+at v=(0)+(9.8)(1.85) v=18.13 m/s [/tex]
This still needs to be converted to m/h:
[tex]18.13m/s = 18.13\times 3600 metres/h=65628 metres/hour 65628 metres/hour = 65628\div1600 mi/h = 40.7925 mi/h = 41 mi/hr (2 significant figures) [/tex]
Thank you for choosing our service. We're dedicated to providing the best answers for all your questions. Visit us again. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.