Answered

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How do I solve 4cos^2 x -1=0

Sagot :

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[tex] (cosx)^{2} = 1/4[/tex] <=> cosx = +1/2 or cosx = -1/2;
cosx = +1/2 => x = +π/3 + 2kπ, where k is an integer or x = -π/3 + 2kπ, where k is an integer;
cosx = -1/2 => x = +2π/3 + 2kπ, where k is an integer or x = -2π/3 + 2kπ, where k is an integer;

Answer:

pi/3? 2pi/3?

Step-by-step explanation:

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