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Sagot :
To find value of y in times o x we have to transfrom this equation.
LEts do this
x-0.25y=1.5 /-x subtract x both sides
-0.25y=1.5-x /*4 multiply by 4 both sides
-0.25y*4=4(1.5-x)
-1y=6-4x /*-1 multiply both sides by -1
y=4x-6
LEts do this
x-0.25y=1.5 /-x subtract x both sides
-0.25y=1.5-x /*4 multiply by 4 both sides
-0.25y*4=4(1.5-x)
-1y=6-4x /*-1 multiply both sides by -1
y=4x-6
x-0.25y = 1.5 Rearrange the equation with y on the left hand side.
Since we are solving for y.
-0.25y = 1.5 -x
-0.25y = -x + 1.5 Divide both sides by -0.25.
y = (-x + 1.5)/-0.25
y = -4*(-x +1.5) = 4x -6.
y = 4x - 6.
Since we are solving for y.
-0.25y = 1.5 -x
-0.25y = -x + 1.5 Divide both sides by -0.25.
y = (-x + 1.5)/-0.25
y = -4*(-x +1.5) = 4x -6.
y = 4x - 6.
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