Answered

Welcome to Westonci.ca, your one-stop destination for finding answers to all your questions. Join our expert community now! Get immediate answers to your questions from a wide network of experienced professionals on our Q&A platform. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.

it takes 56.6 joules of energy to raise the temperature of 150 milliliters of water from 5 degrees Celsius to 95 degree Celsius if you use an electric water heater that is 60% efficient how many kilojoules of energy will the heater actually use by the time the water reaches it's final temperature

Sagot :

ollieboyne
If 56.6J = 60%,

then 56.6/0.6 =  94.3333 J = 0.0943... kJ

The rest of the information (mL and temperature change) isn't needed for the answer...
thomasgallagher98
ANSWER: 94.33 J
EXPLANATION
I'm assuming this is a multi-part question as most of these values aren't needed for this specific question as if we know that 56.6 J is needed but the heater only uses 60% efficiently, 56.6 is 60% of the heater's total required value to raise this amount of water by this much.
Simply multiply up:
60% = 56.6
⇒ 10% = 9.4333
⇒ 100% = 94.33333.... J
(although we cannot have recurring decimals in Physics so stop at a certain point and mention the number of decimal places/significant figures)

Visit us again for up-to-date and reliable answers. We're always ready to assist you with your informational needs. We appreciate your time. Please come back anytime for the latest information and answers to your questions. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.