Answered

Discover the best answers at Westonci.ca, where experts share their insights and knowledge with you. Explore thousands of questions and answers from a knowledgeable community of experts on our user-friendly platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.

How many mg of a metal containing 45% nickel must be combined with 6mg of pure nickel to form an alloy containing 78% nickel?

Sagot :

ollieboyne
let's call the mass of 45% nickel x.

45x + (100 x 6) = 78 x total mass

the total mass is 6 + x, so:

45x + 600 = 78(6 + x)
45x + 600 = 468 + 78x
600-468 = 78x - 45x
132 = 33x
x = 132/33
x = 4 g

hope this helps :)
Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.