At Westonci.ca, we make it easy for you to get the answers you need from a community of knowledgeable individuals. Discover a wealth of knowledge from experts across different disciplines on our comprehensive Q&A platform. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.

How many mg of a metal containing 45% nickel must be combined with 6mg of pure nickel to form an alloy containing 78% nickel?

Sagot :

let's call the mass of 45% nickel x.

45x + (100 x 6) = 78 x total mass

the total mass is 6 + x, so:

45x + 600 = 78(6 + x)
45x + 600 = 468 + 78x
600-468 = 78x - 45x
132 = 33x
x = 132/33
x = 4 g

hope this helps :)
Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.