Answered

Welcome to Westonci.ca, where your questions are met with accurate answers from a community of experts and enthusiasts. Get detailed answers to your questions from a community of experts dedicated to providing accurate information. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.

Solve each system algebraically 3x+6y=-6 5x-2y=14 Help!!

Sagot :

ollieboyne
If you multiply the second equation by 3, it becomes:

15x - 6y = 42

Then add the two equations together:

3x + 6y = -6
15x - 6y = 42
+

18x = 36
x = 2

substitute x back into the first equation:

3(2)+6y = -6
6 + 6y = -6
6y = -12
y = -2

So x=2,y=-2
luana
[tex] \left \{ {{3x+6y=-6} \atop {5x-2y=14\ \ | *3}} \right. \\\\ \left \{ {{3x+6y=-6} \atop {15x-6y=42}} \right.\\\+-----\\Addition\ method\\\\ 18x=36\ \ \ | divide\ by\ 18\\\\x=2\\\\2y=5x-14\\\\ y=\frac{5x-14}{2}=\frac{5*2-14}{2} =\frac{10-14}{2}=-2\\\\Solution\\ \left \{ {{y=-2} \atop {x=2}} \right. [/tex]
We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.