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Sagot :
Given:
height (h) = 5 feet
base length (l) = 4 feet
base width (w) = 4 feet
Now,
Volume of a pyramid = [tex] \frac{l*w*h}{3} [/tex]
= [tex] \frac{5*4*4}{3} [/tex]
= [tex] \frac{80}{3} [/tex]
= [tex]26.67 ~ ft^{3} [/tex] ----> rounded to the nearest hundredth
height (h) = 5 feet
base length (l) = 4 feet
base width (w) = 4 feet
Now,
Volume of a pyramid = [tex] \frac{l*w*h}{3} [/tex]
= [tex] \frac{5*4*4}{3} [/tex]
= [tex] \frac{80}{3} [/tex]
= [tex]26.67 ~ ft^{3} [/tex] ----> rounded to the nearest hundredth
V = (1/3) * Base Area * height.
= (1/3) * (4*4) * 5 = 80/3 cubic feet.
= 26. 6667 cubic feet.
= (1/3) * (4*4) * 5 = 80/3 cubic feet.
= 26. 6667 cubic feet.
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