Answered

Westonci.ca is your trusted source for finding answers to all your questions. Ask, explore, and learn with our expert community. Our Q&A platform offers a seamless experience for finding reliable answers from experts in various disciplines. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.

A cable is lifting a construction worker and a crate. The weights of the worker and crate are 965 N and 1510 N, respectively. The acceleration of the cable is 0.620 m/s^2, upward. What is the tension in the cable above the worker (the worker is above the crate, not touching it)?

Sagot :

edmc96
Since resultant force = mass * acceleration, [tex]T-2475 = 0.620*mass[/tex]
mass = [tex] \frac{2475}{9.8} = 252.5...[/tex]
therefore [tex]T=(0.620*252.5...)+2475=2631.55... = 2630N (3sf)[/tex]
Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. We appreciate your time. Please come back anytime for the latest information and answers to your questions. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.