lilybugged
Answered

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Prove the identity: cos(3x) + cos(x) = 2cos(2x)cos(x)
I'm almost done with my homework, just got stuck on this one.

Sagot :

kate200468
[tex]cos \alpha +cos \beta =2\cdot cos \frac{ \alpha + \beta }{2} \cdot cos \frac{ \alpha - \beta }{2}\\-----------------\\\\ \alpha =3x\ \ \ and\ \ \ \beta =x\\\\[/tex]

[tex]L=cos \alpha +cos \beta =cos(3x)+cos(x)\\\\\Rightarrow\ \ \ 2\cdot cos \frac{ \alpha + \beta }{2} \cdot cos \frac{ \alpha - \beta }{2}=2\cdot cos \frac{3x+x}{2} \cdot cos \frac{3x-x}{2} =\\\\.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ =2\cdot cos \frac{4x}{2} \cdot cos \frac{2x}{2} =\\\\.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ =2\cdot cos(2x)\cdot cos (x)=R[/tex]
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