Answered

At Westonci.ca, we make it easy to get the answers you need from a community of informed and experienced contributors. Explore thousands of questions and answers from knowledgeable experts in various fields on our Q&A platform. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

If the product of two positive fractions a and b is 15/56, find three pairs for possible values for a and b

Sagot :

RhysH
all you have to do is find pairs of factor for both 15 and 56
e.g. 1,15   3,5 
      1.56    2, 28   4, 14

so three possibilities could be
1/1 x 15/56
3/4 x 5/14 
1/2 x 15/28

Answer

Find out the three pairs for possible values for a and b .

To prove

As given

[tex]The\ product\ of\ two\ positive\ fractions\ a\ and\ b\ is\ \frac{15}{56} .[/tex]

i.e it is written in the form.

[tex]a\times b = \frac{15}{56}[/tex]

When

[tex]a = \frac{3}{2} , b = \frac{5}{28}[/tex]

Than

[tex]\frac{3\times 5}{2\times 28} = \frac{15}{56}[/tex]

When

[tex]a = \frac{3}{4} , b = \frac{5}{14}[/tex]

Than

[tex]\frac{3\times 5}{4\times 14} = \frac{15}{56}[/tex]

When

[tex]a = \frac{1}{2} , b = \frac{15}{28}[/tex]

Than

[tex]\frac{1\times 15}{2\times 28} = \frac{15}{56}[/tex]

Hence proved



Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.