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Rewrite the equation in slope-intercept form, identify slope, and the y-intercept of the line.

-x-10y=20

Sagot :

RhysH
rearrange equation to get y as subject
-1x-10y = 20
10y = -1x - 20
y = -1x/10 -2

so the slope is -1/10 and the y intercept -2
konrad509
[tex]-x-10y=20\\ -10y=x+20\\ \boxed{y=-\frac{1}{10}x-2}\\\\ \boxed{m=-\frac{1}{10}}\\\\ -0-10y=20\\ -10y=20\\ \boxed{y=-2} [/tex]
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