Answered

Westonci.ca offers fast, accurate answers to your questions. Join our community and get the insights you need now. Get immediate and reliable answers to your questions from a community of experienced professionals on our platform. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

A motorcycle stunt driver zooms off the end of a cliff at a speed of 30 meters per second. If he lands after 0.75 seconds, what is the height of the cliff?

Sagot :

ollieboyne
[tex]u = 30ms^{-1} \\t = 0.75s \\a = 9.8ms^{-2} (Gravity) \\s = ?[/tex]

[tex]s = ut + \frac{1}{2}at^2 \\s = (30)(0.75)+ \frac{1}{2}(9.8)(0.75)^2 \\s = 22.5 + 2.75625 \\s = 25.25625[/tex]

s = 25.3 m (3 sf)

Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.