shannonrowland
Answered

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First five terms of n2+5

Sagot :

TylerK
n=1 --- 1(2)+5 --- 2+5 --- 7
n=2 --- 2(2)+5 --- 4+5 --- 9
n=3 --- 3(2)+5 --- 6+5 --- 11
n=4 --- 4(2)+5 --- 8+5 --- 13
n=5 --- 5(2)+5 --- 10+5 --- 15
[tex]a_n=n^2+5\\\\a_1=1^2+5=1+5=6\\\\a_2=2^2+5=4+5=9\\\\a_3=3^2+5=9+5=14\\\\a_4=4^2+5=16+5=21\\\\a_5=5^2+5=25+5=30[/tex]
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