At Westonci.ca, we provide clear, reliable answers to all your questions. Join our vibrant community and get the solutions you need. Explore thousands of questions and answers from knowledgeable experts in various fields on our Q&A platform. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.

There are 8 red, 5 yellow and 7 green cubes in a box. What is the probability of drawing a yellow cube and then a green cube,  if the first cube is not replaced before the second cube is drawn?

Sagot :

Step 1: find out how many cubes are there in total.
There are 20 cubes total because 8+5+7 = 20

Step 2: find out how many yellow cubes you have.
In this problem you have 5 yellow cubes out of 20 cubes. So you chances of grabbing a yellow cube is 5 out of 20.

Step 3: simplify. You can simplify 5/20 to 1/5. So you have a 1/5 chance of grabbing a yellow cube.

Step 4: now find how many cube are green. You have 7 green cubes. Because you took out one cube and didn't replace it you now have 19 cubes. So you have a 7/19 chance of grabbing a green cube.

Step 5: now multiply 7/19 times 1/5. Please note you can not simplify 7/19 because 7 and 19 are prime numbers.

Answer 7/95 which is roughly around .073 or 7.3%

i think thats a 1 in 20th chance