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Sagot :
x+y =92
x -y =20
------------ (subtract the y)
2x= 112
/2 /2
x=56
56+y=92 (substitute x with 56)
-56 -56
y=36
x = 56 and y = 36
x -y =20
------------ (subtract the y)
2x= 112
/2 /2
x=56
56+y=92 (substitute x with 56)
-56 -56
y=36
x = 56 and y = 36
The two numbers in question obtained by creating a system of equations are 56 and 36
Let the two numbers be : a and b
- a + b = 92 ___(1)
- a - b = 20.___(2)
From (2):
- a = 20 + b. ____(3)
Substitute (3) into (1)
a + b = 92
20 + b + b = 92
20 + 2b = 92
2b = 92 - 20
2b = 72
b = 72/2
b = 36
From (3) :
a = 20 + 36
a = 56
Therefore, the two numbers are 56 and 36
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