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Sagot :
first subtract 100v² from both sides to get:
C²L²=100c²-100v²
Then divide both sides by C²:
L²=(100c²-100v²)/C²
Then take the square root of both sides:
L=+ or - the square root of (100c²-100v²)/C²
C²L²=100c²-100v²
Then divide both sides by C²:
L²=(100c²-100v²)/C²
Then take the square root of both sides:
L=+ or - the square root of (100c²-100v²)/C²
Answer:
L = ±√( (100c² - 100v²) / C² )
Step-by-step explanation:
You're just doing reverse PEMDAS.
So first get all the values correlated with L on one side and the non-L values on the other side using subtraction/addition.
Then remove all coefficient using multiplication/division.
Then take the sqareroot to get rid of the squre on the v.
Remember that taking squareroot gives a ± answer because
(x)² = (-x)²

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