At Westonci.ca, we provide reliable answers to your questions from a community of experts. Start exploring today! Get quick and reliable solutions to your questions from a community of experienced experts on our platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.
Sagot :
y = 3
x = -4
(2x + y = -5)3 = 6x + 3y = -15 = 6x + 3y = -15
(3x + 5y = 3)2 = -(6x + 10y = 6) = -6x - 10y = -6
-7y = -21 : y = 3
(then we substitute y into equation #1)
2x + 3 = -5
2x = -8
x = -4
x = -4
(2x + y = -5)3 = 6x + 3y = -15 = 6x + 3y = -15
(3x + 5y = 3)2 = -(6x + 10y = 6) = -6x - 10y = -6
-7y = -21 : y = 3
(then we substitute y into equation #1)
2x + 3 = -5
2x = -8
x = -4
2x + y = -5 .........(i)
3x + 5y = 3.........(ii)
Now which do you want us to eliminate first, x or y? I hear you saying y. So we are going to eliminate y first.
But if we look at equations (ii) we see that y has 5y, so we multiply equation (i) by 5, so that it has 5y also.
2x + y = -5 .........(i) (x5).
3x + 5y = 3.........(ii)
5*(2x + y) = 5*(-5)
10x + 5y = -25.............(iii).
The new equation becomes (iii), and we can now compare (ii) and (iii)
3x + 5y = 3.........(ii)
10x + 5y = -25.............(iii)
Since we have now made 5y on both equations, we can eliminate the y, by subtracting.
Equation (ii) Minus (iii).
We perform subtraction before the equality sign and after the equality sign, like in normal subtraction. The xs would subtract the xs and the ys would subtract the ys.
(3x-10x) + (5y -5y) = 3 - (-25)
-7x + 0y = 3 +25 . Minus Minus is Plus.
-7x = 28. Divide both sides by 7.
x = 28/(-7)
x = -4.
Now we have gotten x, so we can now substitute x = -4, in either equations (i) or (ii). Let us use (i).
2x + y = -5 .........(i) x = -4.
2(-4) + y = -5.
-8 + y = -5.
y = -5 +8. (When -8 crossed the equality sign to other side, sign changed)
y = 8-5
y =3.
Therefore x = - 4, y =3. That's it. Cheers.
3x + 5y = 3.........(ii)
Now which do you want us to eliminate first, x or y? I hear you saying y. So we are going to eliminate y first.
But if we look at equations (ii) we see that y has 5y, so we multiply equation (i) by 5, so that it has 5y also.
2x + y = -5 .........(i) (x5).
3x + 5y = 3.........(ii)
5*(2x + y) = 5*(-5)
10x + 5y = -25.............(iii).
The new equation becomes (iii), and we can now compare (ii) and (iii)
3x + 5y = 3.........(ii)
10x + 5y = -25.............(iii)
Since we have now made 5y on both equations, we can eliminate the y, by subtracting.
Equation (ii) Minus (iii).
We perform subtraction before the equality sign and after the equality sign, like in normal subtraction. The xs would subtract the xs and the ys would subtract the ys.
(3x-10x) + (5y -5y) = 3 - (-25)
-7x + 0y = 3 +25 . Minus Minus is Plus.
-7x = 28. Divide both sides by 7.
x = 28/(-7)
x = -4.
Now we have gotten x, so we can now substitute x = -4, in either equations (i) or (ii). Let us use (i).
2x + y = -5 .........(i) x = -4.
2(-4) + y = -5.
-8 + y = -5.
y = -5 +8. (When -8 crossed the equality sign to other side, sign changed)
y = 8-5
y =3.
Therefore x = - 4, y =3. That's it. Cheers.
Thanks for using our service. We aim to provide the most accurate answers for all your queries. Visit us again for more insights. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Thank you for visiting Westonci.ca, your go-to source for reliable answers. Come back soon for more expert insights.
