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-3(10b+10)+5(b+2) solve

Sagot :

[tex]-3(10b+10)+5(b+2)\\=-3(10b)-3(10)+5(b)+5(2)\\=-30b-30+5b+10\\=(-30b+5b)+(-30+10)\\=-25b+(-20)\\\boxed{=-25b-20}[/tex]
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