jadiesilva
Answered

Westonci.ca is your go-to source for answers, with a community ready to provide accurate and timely information. Get immediate and reliable solutions to your questions from a community of experienced experts on our Q&A platform. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

Joaquin has created a small treasure map that is in the shape of a square. He decides to make a larger version of the map, and on this new map he increases each side by 6 inches. The area of this larger version of the map is 121 square inches. What are the dimensions of his original, smaller map?

Sagot :

(l+6)(l+6)=121=l^2+6l+6l+36
l^2+12l-85=(l-5)(l+17)
l=5 or l =-17 
cannot be negative
therefore was a 5 by 5 map


Limosa

Answer:

The length of a side of the smaller map is 5 inches.

Step-by-step explanation:

Lets take the original length of a side of the Map is [tex]x[/tex] inches.

So the length of a side if the new Map = [tex]x+6[/tex] inches.

Area of a square = (Length of a side)²

[tex]121=(x+6)^{2}[/tex]

[tex]\sqrt{121} =\sqrt{(x+6)^{2}  }[/tex]

So, either

[tex]11=x+6[/tex]              or             [tex]-11=x+6[/tex]

[tex]5=x[/tex]                   or            [tex]-17=x[/tex]

[tex]x[/tex] cannot be a negative value as it is a length of a square.

Therefore. the length of a side of the smaller map is 5 inches.


Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.