jadiesilva
Answered

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Sonya found that x = - 4/3 is one solution of (6x + 4)2 = ?. The other solution is x = ? .

Sagot :

Solution: The value of (?) is 16 and the other value of x is 0.

Explanation:

Let the value of (?) is C.

It the given equation is [tex](6x+4)^2=C[/tex]. It can be written as [tex](6x+4)^2-C=0[/tex]

Since [tex]x=\frac{-4}{3}[/tex] is the solution of the given equation, therefore [tex]x=\frac{-4}{3}[/tex] will satisfies the given equation.

Put [tex]x=\frac{-4}{3}[/tex]

[tex](6(\frac{-4}{3}) +4)^2-C=0\\(-8+4)^2-C=0\\{-4}^2-C=0\\C=16[/tex].

The given equation become [tex](6x+4)^2+16=0[/tex].

[tex](6x+4)^2=16[/tex]

[tex]6x+4=4\\6x=0\\x=0[/tex]

[tex]6x+4=-4\\6x=-8\\x=\frac{-4}{3}[/tex]

Therefore the value of (?) is 16 and the other value of x is 0.

bluberry01

Answer:

16, 0

Step-by-step explanation:

Sonya found that x = - 4/3 is one solution of (6x + 4)2 = 16. The other solution is x = 0.

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