Westonci.ca is your go-to source for answers, with a community ready to provide accurate and timely information. Experience the convenience of getting accurate answers to your questions from a dedicated community of professionals. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.
Sagot :
[tex]x^2- 40 = 0\ \ \ \Leftrightarrow\ \ \ x^2-(2 \sqrt{10} )^2=0\\\\\ \ \ \Leftrightarrow\ \ \ (x-2 \sqrt{10} )(x+2 \sqrt{10} =0\\\\ \ \ \Leftrightarrow\ \ \ x=2 \sqrt{10} \ \ \ \ \ or\ \ \ \ \ x=-2 \sqrt{10[/tex]
Answer:
Given the quadratic equation: [tex]x^2-40=0[/tex]
Addition property of equality states that you add the same number to both sides of an equation.
Step 1.
[tex]x^2-40=0[/tex]
Add 40 to both sides of an equation:
[tex]x^2-40+40=0+40[/tex]
Simplify:
[tex]x^2=40[/tex] ......[1]
Step 2.
Take square root both sides in equation [1]; we have
[tex]\sqrt{x^2} =\sqrt{40}[/tex]
Simplify:
[tex]x=\pm \sqrt{40} =\pm 2\sqrt{5}[/tex]
Hence, the roots for the given equation is x = [tex]+2\sqrt{5}[/tex] , [tex]-2\sqrt{5}[/tex] .
Therefore, for solving the quadratic equation the first step is; Adding 40 to both sides of an equation.
Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.