Welcome to Westonci.ca, where finding answers to your questions is made simple by our community of experts. Discover in-depth answers to your questions from a wide network of experts on our user-friendly Q&A platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

Please help!
You must roll a total of 9 on two number cubes to win the game. Alex must roll a 6. Who is more likely to win the game on the next turn? Explain.


Sagot :

There are 36 possible combinations for 2 dices because there are 6 numbers per di
6 has 5 combinations because you must use 2 dices
1+5
2+4
3+3
4+3
5+1
So Alex has [tex] \frac{6}{36} [/tex] or [tex] \frac{1}{6} [/tex] chance of getting exactly 6

While 9 has 4 combinations
3+6
4+5
5+4
6+3
So you have [tex] \frac{4}{36} [/tex] or [tex] \frac{1}{9} [/tex] chance of getting exactly 9

So Alex has a better chance

To roll a 9, you need a combination of 3 and 6, or 4 and 5, in any order. To roll a 6, Alex needs a combination of 1 and 5, 2 and 4, or 3 and 3, in any order. There are 4 possible ways to roll a 9 and 5 possible ways to roll a 6, so Alex is more likely to win

Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.