amazingphil
Answered

Find the best solutions to your questions at Westonci.ca, the premier Q&A platform with a community of knowledgeable experts. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.


PLEASE HELP!!! THERE IS A PICTURE ATTACHED
Francisco is playing a game with 3 green, 2 yellow, 4 red, and 3 black marbles in a bag. He has calculated the probability of drawing a yellow marble, not replacing it, and then drawing a red marble. Explain the error in his solution.(the picture is Fransisco's work)

PLEASE HELP THERE IS A PICTURE ATTACHED Francisco Is Playing A Game With 3 Green 2 Yellow 4 Red And 3 Black Marbles In A Bag He Has Calculated The Probability class=

Sagot :

Well, the problem is that he does not replace the first marble after he draws it. Therefore, yes, he has a 2/12 probability of drawing a yellow marble first, but then he has a 4/11 probability of drawing a red marble second, not 4/12. This is because there are going to only be 11 marbles left in the bag after he draws the first marble and does not replace it.

The correct answer would be:
(2/12)(4/11)=8/132=4/66=2/33
MissLorwee

Answer:

Step-by-step explanation:

ample Response: The events are dependent, so the sample space changes for the second draw. After drawing the first marble, there are only 11 marbles left. The probability is (  

2

12

) (  

4

11

)  =  

8

132

, or  

2

33

.

We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.