Answered

At Westonci.ca, we provide clear, reliable answers to all your questions. Join our vibrant community and get the solutions you need. Experience the ease of finding accurate answers to your questions from a knowledgeable community of professionals. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

Identify the limiting reactant when 6.33 g of H2SO4 reacts with 5.92 g of NaOH to produce Na2SO4 and water.

Sagot :

Yipes
H₂SO₄:

m=6.33g
M=98g/mol

n = m/M = 6.33g/98g/mol ≈ 0,065mol

NaOH:

m=5.29g
M=40g/mol

n = m/M = 5.29g/40g/mol ≈ 0,132mol

2NaOH        +         H₂SO₄          ⇒ Na₂SO₄ + 2H₂O
2mol             :          1mol            :     1mol
0.132mol     :          0.065mol    :     0.065mol
too much                 limiting
                                  reactant

Limiting reactant is H₂SO₄.
We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.