Answered

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Identify the limiting reactant when 6.33 g of H2SO4 reacts with 5.92 g of NaOH to produce Na2SO4 and water.

Sagot :

Yipes
H₂SO₄:

m=6.33g
M=98g/mol

n = m/M = 6.33g/98g/mol ≈ 0,065mol

NaOH:

m=5.29g
M=40g/mol

n = m/M = 5.29g/40g/mol ≈ 0,132mol

2NaOH        +         H₂SO₄          ⇒ Na₂SO₄ + 2H₂O
2mol             :          1mol            :     1mol
0.132mol     :          0.065mol    :     0.065mol
too much                 limiting
                                  reactant

Limiting reactant is H₂SO₄.
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