Answered

Welcome to Westonci.ca, the place where your questions are answered by a community of knowledgeable contributors. Get detailed answers to your questions from a community of experts dedicated to providing accurate information. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

Given that cos (x) = 1/3, find sin (90 - x)

Sagot :

A/c to trigonometric relations, sin(90 - x) = cos(x),
that means sin(90 - x) = cos(x) = 1/3.

Answer:

[tex]\sin(90^{\circ} - x)=\frac{1}{3}[/tex]

Step-by-step explanation:

Given: [tex]\cos (x)=\frac{1}{3}[/tex]

We have to find the value of [tex]\sin(90^{\circ} - x)[/tex]

Since Given [tex]\cos (x)=\frac{1}{3}[/tex]

Using trigonometric identity,

[tex]\sin(90^{\circ} - \theta)=\cos\theta[/tex]

Thus, for  [tex]\sin(90^{\circ} - x)[/tex] comparing , we have,

[tex]\theta=x[/tex]

We get,

[tex]\sin(90^{\circ} - x)=\cos x=\frac{1}{3}[/tex]

Thus, [tex]\sin(90^{\circ} - x)=\frac{1}{3}[/tex]