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clyde makes a copy of an 8 in. x 10 in. photo, reducing it to 3/4 of its size. what are the dimensions of the new photo?

Sagot :

To get the reduced dimensions we have to multiply each dimension by 3/4 factor, so
[tex]8 \frac{3}{4}= 2\frac{3}{1}=6 [/tex] - first dim
[tex]10* \frac{3}{4}= \frac{30}{4}=7.5 [/tex] -second dim
Answer is  6x7.5
elizaleewilliam

Clyde should have applied the power of a power rule and multiplied the exponents instead of adding them. The simplified form should be j to the 16th power.

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