Westonci.ca offers fast, accurate answers to your questions. Join our community and get the insights you need now. Join our platform to connect with experts ready to provide accurate answers to your questions in various fields. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

Soo-Jin and mary had an equal number of beads. After soo-jin gave 54 beads to mary. Mary had 7 times as many beads as soo-jin how many beads did they have altogether?

Sagot :

i cant really get the specific answer but i guess that both of them have 55.96 and then Soo-jin gave 54 to Mary and it left 1.96 so Mary had 109.96 ....1.96(7 times) is exactly 111.120some so ...i think altogether they have is 111.92..that is all i can think for this question.hope it help.
[tex]x\ \ \rightarrow\ \ the\ number\ of\ Soo-Jin's\ beads\\y\ \ \rightarrow\ \ the\ number\ of\ Mary's\ beads\\\\x=y\ \ \ \ \ and\ \ \ \ \ 7\cdot(x-54)=y+54\\\\7x-7\cdot54=x+54\\7x-7\cdot54-x+7\cdot54=x+54-x+7\cdot54\\6x=8\cdot54\ \ /:6\\\\x= \frac{\big{8\cdot54}}{\big{6}} \\\\x= 8\cdot9\\\\x=72\ \ \ \Rightarrow\ \ \ y=72\ \ \ \Rightarrow\ \ \ x+y=2\cdot72=144\\\\Ans.\ \ \ 144\ beads\ altogether[/tex]