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Workers load a 500kg safe onto an elevator that lifts it 90m to the twentieth floor of a building. How much work did the elevator do on the safe?

Sagot :

Work is Force X Distance. The force is equal to mass X acceleration (F=MA). In this case the acceleration is gravity, which is 9.81 m/s^2. So you multiply 500 by 9.81 to get 4905 Newtons (N). This is the amount of force required to lift the safe. Multiply this force by the distance, which in this case is 90 meters. This gives you 441450 Newton Meters (N*m) of work. 1 N*m is equivalent to 1 Joule (J), so the answer can be written as 441450 Joules (J).
Lanuel

The amount of work done on the safe by the elevator is equal to 441,000 Joules or 441 Kilojoules.

Given the following data:

  • Mass of safe = 500 kg
  • Displacement = 90 meters

Scientific data:

  • Acceleration due to gravity = 9.8 [tex]m/s^2[/tex]

To determine the amount of work done on the safe by the elevator:

First of all, we would calculate the magnitude of force that is acting on the safe;

[tex]Force = mg\\\\Force = 500 \times 9.8[/tex]

Force = 4900 Newton

Now, we can determine the amount of work done on the safe:

Mathematically, work done is given by the formula:

[tex]Work\;done = Force \times displacement\\\\Work\;done =4900 \times 90[/tex]

Work done = 441,000 Joules or 441 Kilojoules.

Read more here: https://brainly.com/question/1281428

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