Answered

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Which number supports the given conjecture?

If a number is divisible by both 2 and 3, then the number is also divisible by 6.



A.
16


B.
23


C.
27


D.
36

Sagot :

SlowZasob
A. 16 is divisible by 2 but not divisible by 3
B. 23 is not divisible neither by 2 nor 3
C. 27 is not divisible by 2, however it's divisible by 3
D. 36 is divisible both by 2 and 3

So the only number we can focus on is 36:

36 ÷ 2 = 18
36 ÷ 3 = 12
36 ÷ 6 = 6

Answer: D, 36 supports the given conjecture.
D. 36 because 36/ 2= 18 36/ 3= 12 36/ 6= 6
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