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Sagot :
A. 16 is divisible by 2 but not divisible by 3
B. 23 is not divisible neither by 2 nor 3
C. 27 is not divisible by 2, however it's divisible by 3
D. 36 is divisible both by 2 and 3
So the only number we can focus on is 36:
36 ÷ 2 = 18
36 ÷ 3 = 12
36 ÷ 6 = 6
Answer: D, 36 supports the given conjecture.
B. 23 is not divisible neither by 2 nor 3
C. 27 is not divisible by 2, however it's divisible by 3
D. 36 is divisible both by 2 and 3
So the only number we can focus on is 36:
36 ÷ 2 = 18
36 ÷ 3 = 12
36 ÷ 6 = 6
Answer: D, 36 supports the given conjecture.
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