Answered

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48dm3 of a gas has a mass of 262g how many moles is this? What is the Mr? What must this element be?

Sagot :

Yipes
[tex]n=\frac{V}{V_{0}}\\\\ V=48dm^{3}\\ V_{0}=22.4\frac{dm^{3}}{mol}\\\\ n=\frac{48dm^{3}}{22.4\frac{dm^{3}}{mol}}\approx2mol\\\\ n=\frac{m}{M_{r}} \ \ \ \Rightarrow \ \ \ M_{r}=\frac{m}{n}\\\\ m=262g\\ n=2mol\\\\ M_{r}=\frac{262g}{2mol}=131\frac{g}{mol}[/tex]

This element must be xenon.
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