Answered

Find the best solutions to your questions at Westonci.ca, the premier Q&A platform with a community of knowledgeable experts. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

How do tou find the acceleration of a car between two points on a velocity-time variation graph

Sagot :

dannyboy49
a = ∆v/∆t
Say velocity is on the y-axis and time in on the x-axis. If you take the points (2,1) and (5,8) for example, the difference between the velocity points is 8-1 = 7. This difference is the change in velocity (i.e. ∆v, ∆ means change in) between these two points. The same goes for time: 5-2 = 3.
So we've concluded that in this example, ∆v = 7 and ∆t = 3. Now put these into the equation above to find acceleration:
7/3 = 2.333...
So the acceleration between these two points on the graph is 2.333...(recurring), or as a fraction, 7/3.
AL2006
The magnitude of acceleration is

(change in speed) divided by (time for the change) .

Between the two points on the graph ...

-- Find the change in speed. (usually the y-axis)
-- Find the change in time. (usually the x-axis)

Divide (change in time) by (change in speed) between the two points.
That quotient is the average magnitude of acceleration during that time.

If the graph happens to be a straight line, then the magnitude of acceleration
is just the slope of the line.
Thank you for visiting our platform. We hope you found the answers you were looking for. Come back anytime you need more information. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.