Answered

Looking for reliable answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

What is the axis of symmetry for f(x) = −5x2 − 20x − 10

Sagot :

carlosego
For this case we have the following function:
 [tex]f(x) = -5x^2 - 20x - 10 [/tex]
 To find the axis of symmetry, the first thing to do is to derive the function.
 We have then:
 [tex]f '(x) = -10x - 20 [/tex]
 Equaling zero we have:
 [tex]-10x - 20 = 0 [/tex]
 We clear the value of x.
 We have then:
 [tex]-10x = 20 x = -20/10 x = -2 [/tex]
 Answer:
 The axis of symmetry is given by:
 x = -2

Answer:

x=  -2 is the axis of symmetry for [tex]f(x) = -5x^2-20x-10[/tex]

Step-by-step explanation:

A quadratic equation is in the form of [tex]y =ax^2+bx+c[/tex] .......[1],

then the axis of symmetry is given by:-

[tex]x = -\frac{b}{2a}[/tex]                   ....[2]

As per the statement:

[tex]f(x) = -5x^2-20x-10[/tex]

On comparing with equation [1] we have;

a = -5, b = -20 and c = -10

Substitute these values in [2] we have;

[tex]x = -\frac{-20}{2 \cdot (-5)}[/tex]

⇒[tex]x = -\frac{-20}{-10}[/tex]

Simplify:

x =  -2

Therefore, the axis of symmetry for the given function is, x= -2.

Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.