Answered

Westonci.ca is the premier destination for reliable answers to your questions, provided by a community of experts. Discover precise answers to your questions from a wide range of experts on our user-friendly Q&A platform. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.

What is the axis of symmetry for f(x) = −5x2 − 20x − 10

Sagot :

carlosego
For this case we have the following function:
 [tex]f(x) = -5x^2 - 20x - 10 [/tex]
 To find the axis of symmetry, the first thing to do is to derive the function.
 We have then:
 [tex]f '(x) = -10x - 20 [/tex]
 Equaling zero we have:
 [tex]-10x - 20 = 0 [/tex]
 We clear the value of x.
 We have then:
 [tex]-10x = 20 x = -20/10 x = -2 [/tex]
 Answer:
 The axis of symmetry is given by:
 x = -2

Answer:

x=  -2 is the axis of symmetry for [tex]f(x) = -5x^2-20x-10[/tex]

Step-by-step explanation:

A quadratic equation is in the form of [tex]y =ax^2+bx+c[/tex] .......[1],

then the axis of symmetry is given by:-

[tex]x = -\frac{b}{2a}[/tex]                   ....[2]

As per the statement:

[tex]f(x) = -5x^2-20x-10[/tex]

On comparing with equation [1] we have;

a = -5, b = -20 and c = -10

Substitute these values in [2] we have;

[tex]x = -\frac{-20}{2 \cdot (-5)}[/tex]

⇒[tex]x = -\frac{-20}{-10}[/tex]

Simplify:

x =  -2

Therefore, the axis of symmetry for the given function is, x= -2.

We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.