mch17x
Answered

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how can f(x)=6x^2+5x-6 be factored to reveal the zeros of the function it defines

Sagot :

6 x^2+5 x-6
Factor the quadratic 6 x^2+5 x-6. The coefficient of x^2 is 6 and the constant term is -6. The product of 6 and -6 is -36. The factors of -36 which sum to 5 are -4 and 9. So 6 x^2+5 x-6 = 6 x^2+9 x-4 x-6 = 3 (3 x-2)+2 x (3 x-2):
3 (3 x-2)+2 x (3 x-2)
Factor 3 x-2 from 3 (3 x-2)+2 x (3 x-2):
Answer: |
| (3 x-2) (2 x+3)
Zeros: 2/3 , -3/2
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