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Sagot :
The question is basically asking when do the two equations equal the same thing
2x +1 = -(x-1)^2+3
move the x's all on one side, and the numbers on the other
2x + (x - 1)^2 = +2
multiply out the brackets:
(x - 1)^2
(x - 1)(x -1)
x^2 -2x +1
put that into the equation instead of the brackets:
2x +x^2 -2x +1 = +2
keep all the x's on one side again:
2x +x^2 -2x = 1
The 2x's cancel out, so:
x^2 = +1
square root:
x = √1 = 1
if x = 1 then put that into the equations to find the value of y when they cross:
y=2x+1
y=2(1)+1
y= 2+1 = 3
y = 3
y= -(x-1)^2 +3
y = -((1) -1)^2 +3 = 3
y = 3
so the point where they cross is (1,3).
I think.
not 100% sure
2x +1 = -(x-1)^2+3
move the x's all on one side, and the numbers on the other
2x + (x - 1)^2 = +2
multiply out the brackets:
(x - 1)^2
(x - 1)(x -1)
x^2 -2x +1
put that into the equation instead of the brackets:
2x +x^2 -2x +1 = +2
keep all the x's on one side again:
2x +x^2 -2x = 1
The 2x's cancel out, so:
x^2 = +1
square root:
x = √1 = 1
if x = 1 then put that into the equations to find the value of y when they cross:
y=2x+1
y=2(1)+1
y= 2+1 = 3
y = 3
y= -(x-1)^2 +3
y = -((1) -1)^2 +3 = 3
y = 3
so the point where they cross is (1,3).
I think.
not 100% sure
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