tony05
Answered

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A container has 50 electronic components, of which 10 are defective.
If 8 components are drawn at random from the container, what is the probability that exactly 3 of them are defective?

Sagot :

Coding8with8Valor
(10/50) * (3/8) = .075
.075 * 100 = 7.5% chance of this happening

Answer:

[tex]0.1468 \\= 0.147[/tex]

Step-by-step explanation:

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