kbheffernan48
Answered

Discover the answers you need at Westonci.ca, a dynamic Q&A platform where knowledge is shared freely by a community of experts. Explore in-depth answers to your questions from a knowledgeable community of experts across different fields. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

how? I'm so lost, alsphfbnslq

How Im So Lost Alsphfbnslq class=

Sagot :

konrad509
[tex]D:x-1>0\\ D:x>1\\ \log_3(x-1)=2\\ 3^2=x-1\\ 9=x-1\\ x=10[/tex]
Thank you for your visit. We are dedicated to helping you find the information you need, whenever you need it. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.