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Sagot :
First we have to use conservation of energy, that the heat transferred from gold to the alcohol used to raise the temperature of the alcohol by 2 degrees.
the heat lost by gold = heat required by the methyl
(m of gold)(C of gold)(dTof gold) = (m of ethyl)(C of ethyl)(dT of ethyl)
where;
m of gold is the unknown to be determined
c of gold is the specific heat of gold
dT of gold is the change in temperature in gold
m of ethyl is the mass of ethyl alcohol
C of ethyl is the specific heat of ethyl
dT is the change in temperature in ethyl alcohol
now
mass of gold = unknown
c of gold = 129
dT of gold = 95 - 25 = 68 degrees
m of ethyl = density of ethyl * volume of ethyl
789 X 0.5 X 10^(-3) = 0.3945
mass of gold = 0.3945 kg
the heat lost by gold = heat required by the methyl
(m of gold)(C of gold)(dTof gold) = (m of ethyl)(C of ethyl)(dT of ethyl)
where;
m of gold is the unknown to be determined
c of gold is the specific heat of gold
dT of gold is the change in temperature in gold
m of ethyl is the mass of ethyl alcohol
C of ethyl is the specific heat of ethyl
dT is the change in temperature in ethyl alcohol
now
mass of gold = unknown
c of gold = 129
dT of gold = 95 - 25 = 68 degrees
m of ethyl = density of ethyl * volume of ethyl
789 X 0.5 X 10^(-3) = 0.3945
mass of gold = 0.3945 kg
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