Answered

Looking for trustworthy answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Join our Q&A platform to get precise answers from experts in diverse fields and enhance your understanding. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.

A bar of pure gold is heated to 95.0 degrees Celsius. The specific heat capacity of gold is 1.29 X 10^2. The gold is placed into 500 mL of ethyl alcohol initially at a temperature of 25 Celsius. The final temperature of the mixture is 27.0 Celsius. What is the mass of the gold?

Sagot :

aannad1
First we have to use conservation of energy, that the heat transferred from gold to the alcohol used to raise the temperature of the alcohol by 2 degrees. 
                       the heat lost by gold = heat required by the methyl 
   (m of gold)(C of gold)(dTof gold) = (m of ethyl)(C of ethyl)(dT of ethyl) 
  where;
m of gold is the unknown to be determined
c of gold is the specific heat of gold
dT of gold is the change in temperature in gold
m of ethyl is the mass of ethyl alcohol
C of ethyl is the specific heat of ethyl
dT is the change in temperature in ethyl alcohol
   now
                                        mass of gold = unknown
                                               c of gold = 129
                                  dT of gold = 95 - 25 = 68 degrees
                     m of ethyl = density of ethyl * volume of ethyl
                              789 X 0.5 X 10^(-3) = 0.3945
                                 mass of gold = 0.3945 kg
We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.