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Use log b 2=0.693 and /or log b 7 = 1.946
to find log b 14

Sagot :

[tex]We\ know:log_a(b\cdot c)=log_ab+log_ac\\\\therefore:\\\\log_b14=log_b(2\cdot7)=log_b2+log_b7=0.693+1.946=2.639[/tex]
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