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Sagot :
x-width
2x-3-length
A=lxw
104=(2x-3)(x)
104=2x^2-3x
52=x^2-3/2(x)
52+9/16=x^2-3/2(x)+9/16
841/16=(x-3/4)^2
29/4=x-3/4
x=32/4 or 8
length is 2(8)-3 which is 13 and width is 8
2x-3-length
A=lxw
104=(2x-3)(x)
104=2x^2-3x
52=x^2-3/2(x)
52+9/16=x^2-3/2(x)+9/16
841/16=(x-3/4)^2
29/4=x-3/4
x=32/4 or 8
length is 2(8)-3 which is 13 and width is 8
Answer:
l = 13 m
Step-by-step explanation:
Let's call the width of the rectangle x. Then we can form an expression for the length of the rectangle: 2x - 3
Now we need to form an equation for the area of the rectangle and solve it:
x(2x - 3) = 104
2x² - 3x = 104
2x² - 3x - 104 = 0 - now we need to factorize the equation
(2x + 13)(x - 8) = 0
Now we can say that x = 8 or x = -6.
Because we cannot have a negative length, x = 8 m.
Now we can workout the length using the expression that we formed at the beginning:
2x - 3 = l
2(8) - 3 = l
l = 16 - 3
l = 13 m
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