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Sagot :
a)
v=sqrt(ar)
v^2=ar
r=(v^2)/a
r=(14^2)/39.2
r=5
5 m
b)
v=sqrt(ar)
v^2=ar
a=(v^2)/r
a=(8^2)/2.5
a=25.6
25.6ms^-2
v=sqrt(ar)
v^2=ar
r=(v^2)/a
r=(14^2)/39.2
r=5
5 m
b)
v=sqrt(ar)
v^2=ar
a=(v^2)/r
a=(8^2)/2.5
a=25.6
25.6ms^-2
The smallest radius will be, r = 5 m. And the acceleration of a car is, a = 25.6 m/s².
What is acceleration?
Acceleration is the ratio of the change of the velocity with respect to time or the rate of change of the velocity.
a.The relation between the velocity, the radius of the path, and the acceleration on the circular path is given by :
Acceleration, a = 39.2 m/s²
Velocity of the car, v = 14 m/s
The radius of the path can be calculated using the above formula i.e.
[tex]r=\dfrac{v^2}{a}[/tex]
[tex]r=\dfrac{(14)^2}{39.2}[/tex]
r = 5 m
b. Velocity of the car, v = 8 m/s
The radius of the path, r = 2.5 m
The acceleration of the car is given by :
[tex]a=\dfrac{8^2}{2.5}[/tex]
a = 25.6 square meter.
Therefore, the smallest radius will be, r = 5 m. And the acceleration of a car is, a = 25.6 m/s².
To know more about acceleration follow
https://brainly.com/question/460763
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