Westonci.ca is the ultimate Q&A platform, offering detailed and reliable answers from a knowledgeable community. Discover reliable solutions to your questions from a wide network of experts on our comprehensive Q&A platform. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

please help me I'm desperate.

Please Help Me Im Desperate class=

Sagot :

[tex]D:4x-1>0 \wedge x+2 >0 \wedge x>0\\ D:4x>1 \wedge x>-2 \wedge x>0\\ D:x>\frac{1}{4} \wedge x>0\\ D:x>\frac{1}{4}\\\\ \log(4x-1)-\log(x+2)=\log x\\ \log\frac{4x-1}{x+2}=\log x\\ \frac{4x-1}{x+2}=x\\ x(x+2)=4x-1\\ x^2+2x=4x-1\\ x^2-2x+1=0\\ (x-1)^2=0\\ \boxed{x=1} [/tex]
[tex]\log (4x - 1) - \log (x + 2) = \log x[/tex]
[tex]\log ( \frac{4x - 1}{x + 2} ) = \log x[/tex]
[tex] \frac{4x - 1}{x + 2} = x[/tex]
[tex]4x - 1 = x(x + 2)[/tex]
[tex]4x - 1 = x^2 + 2x[/tex]
[tex]0 = x^2 - 2x + 1[/tex]
[tex]0 = (x - 1)^2[/tex]
⇒ [tex]x = 1[/tex]
We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.