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A 10 kg bowling ball would require what force to accelerate down an alleyway at a rate of 3 m/s2?
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M=
A=

Sagot :

Hello!

A 10 kg bowling ball would require. What force to accelerate down an alleyway at a rate of 3 m/s²  ?

We have the following data:

F (force) = ? (in N or kg.m/s²)

m (mass) = 10 kg

a (acceleration) = 3 m/s²

We apply the data to the Net force formula, we have:

[tex]F =m*a[/tex]

[tex]F = 10\:kg * 3\:\dfrac{m}{s^2}[/tex]

[tex]F = 30\:kg*\dfrac{m}{s^2} \to \boxed{\boxed{F = 30\:N}}\:\:\:\:\:\:\bf\green{\checkmark}[/tex]

Answer:

The force is 30 Newton

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[tex]\bf\purple{I\:Hope\:this\:helps,\:greetings ...\:Dexteright02!}\:\:\ddot{\smile}[/tex]

The force to accelerate down an alley way will be "30 N".

In the given question, the values are:

Mass,

  • m = 10 kg

Acceleration,

  • a = 3 m/s²

As we know the formula for finding the force will be:

→ [tex]Force = Mass\times Acceleration[/tex]

or,

→       [tex]F = m\times a[/tex]

By putting the given values in the formula, we get

→           [tex]= 10\times 3[/tex]

→           [tex]= 30 \ N[/tex]

Thus the above answer is correct.  

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