pinky2007
Answered

Welcome to Westonci.ca, the place where your questions find answers from a community of knowledgeable experts. Connect with a community of experts ready to provide precise solutions to your questions on our user-friendly Q&A platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.

Hydrogen peroxide can be prepared by the reaction of barium peroxide with sulfuric acid according to

Hydrogen Peroxide Can Be Prepared By The Reaction Of Barium Peroxide With Sulfuric Acid According To class=

Sagot :

Yipes
BaO₂ + H₂SO₄ ⇒ BaSO₄ + H₂O₂
169g   :  98g
23.1g  :  mx

mx = [23.1*98g]/169g ≈ 13.4g
Mr = 98g/mol 

n = 13.4g/98g/mol ≈ 0.14mol

Cm = 4.5M
n = 0.14mol

V = 0.14mol/4.5mol/dm³ ≈ 0.031L = 31mL

valenbraca

Answer:

31.43 ml of sulfuric acid is needed to react with 23.1 g of barium peroxide.

Explanation:

For the reaction:

BaO₂(s) + H₂SO₄(aq) ⇒ BaSO₄(s) + H₂O₂(aq)

We need 1 mole of BaO₂ to react with 1 mole of H₂SO₄ and then forming 1 mole of BaSO₄ and 1 mole of H₂O₂.

We know that 4.5 M solution of H₂SO₄ means 4.5 moles of H₂SO₄ in 1000 ml of solution.

Then,

23.1 g BaO₂ × [tex]\frac{1 mole_{BaO_2}}{163.33g_{BaO_2}}[/tex] ×   [tex]\frac{1 mole_{H_{2}SO_{4}}}{1mole_{BaO_2}}[/tex] ×   [tex]\frac{1000ml}{4.5 mole_{H_{2}SO_{4}}}[/tex] = 31.43 ml H₂SO₄

We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.